Question

The kinetic energy of 1 mole of oxygen molecules in $calmo{l}^{-1}$ at ${27}^{\circ }C$ is__.

• A. 300
• B. 600
• C. 900
• D. 800

Answer 1

The correct option is C

900

KE = $\frac{3}{2}nRT$

= $\frac{3}{2}\times 1\times 2\times 300$

= $900calmo{l}^{-1}$