The kinetic energy of - -particle emitted in the - -decay of 88 Ra226 is -given- mass number of Ra-222 u-

The correct option is D 4.871 MeV K · E=4.87 MeV K · E_α=(A 4/A)^Q Q=(A/A 4) × K E_α Q=[226/226 4] × 4.78 Q=226/222× 4.78 Q=4.865 ...

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Byju's Answer

Standard XII

Physics

Law of Radioactivity

The kinetic e...

Question

The kinetic energy of $α - p a r t i c l e$ emitted in the $α - d e c a y$ of $_{88} R a^{226}$ is [given, mass number of Ra=222 u]

5.201 MeV

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3.301 MeV

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6.023 MeV

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4.871 MeV

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Solution

The correct option is D 4.871 MeV
$K \cdot E = 4.87 M e V$
$K \cdot E_{α} = {(\frac{A - 4}{A})}^{Q}$
$Q = (\frac{A}{A - 4}) \times K E_{α}$
$Q = [\frac{226}{226 - 4}] \times 4.78$
$Q = \frac{226}{222} \times 4.78$
$Q = 4.865 m e V$
$(D] Q \approx 4.8 H M e V$

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Similar questions

Q. The kinetic energy of

α

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α

- decay of

_{88} {R a}^{226}

is [ given, mass number of Ra = 222 u ]

Q. A nucleus of mass number 220 decays by

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Suppose a $_{88}^{226} R a$ nucleus at rest and in ground state undergoes $α$ -decay to a $_{86}^{222} R n$ nucleus in its excited state. The kinetic energy of the emitted $α$ particle is found to be $4.44 M e V$ . $_{86}^{222} R n$ nucleus then goes to its ground state by $γ$ -decay. The energy of the emitted $γ$ photon is $k e V$ .

[Given : atomic mass of $_{88}^{226} R a = 226.005 u$ , atomic mass of $_{86}^{222} R n = 222.000 u$ , atomic mass of $α$ particle = $4.000 u, 1 u = 931 M e V / c^{2}, c$ is speed of light]

Q. A nucleus of mass 218 amu in free state decays to emit an

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The kinetic energy of α−particle emitted in the α−decay of 88Ra226 is [given, mass number of Ra=222 u]

The correct option is D 4.871 MeVK⋅E=4.87MeVK⋅Eα=(A−4A)QQ=(AA−4)×KEαQ=[226226−4]×4.78Q=226222×4.78Q=4.865meV (D] Q≈4.8HMeV

The kinetic energy of $α - p a r t i c l e$ emitted in the $α - d e c a y$ of $_{88} R a^{226}$ is [given, mass number of Ra=222 u]

The correct option is D 4.871 MeV
$K \cdot E = 4.87 M e V$
$K \cdot E_{α} = {(\frac{A - 4}{A})}^{Q}$
$Q = (\frac{A}{A - 4}) \times K E_{α}$
$Q = [\frac{226}{226 - 4}] \times 4.78$
$Q = \frac{226}{222} \times 4.78$
$Q = 4.865 m e V$
$(D] Q \approx 4.8 H M e V$