The kinetic energy of an electron emitted when a radiation of frequency 1.0×1015s−1 hits the metal is 2×10−19J. Calculate the threshold frequency of the metal.
A
6.98×1014s−1
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B
7.52×1014s−1
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C
3.23×1014s−1
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D
5.68×1014s−1
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Solution
The correct option is A6.98×1014s−1 According to Einstein's equation,
Kinetic energy =12mev2=h(ν−ν0)
where me = mass of electron ν = frequency of incident radiation νo = Threshold frequency
Given,
Kinetic energy = 2×10−19J
frequency of the incident radiation ν = 1.0×1015s−1