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Question

The kinetic energy of any gas molecule at 0C is:

A
zero
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B
3408 J
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C
2 cal
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D
5.66×1021J
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Solution

The correct option is D 5.66×1021J
The kinetic energy of any gas molecule at 0 deg C is 32kT=32×1.38×1023J/K×(0+273)K=5.66×1021J

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