Given the numbers are in ratio 2 : 3. Let the numbers be 2x and 3x.
Then, their L.C.M. = 6x ( as they are co primes)
⇒ 6x = 48 ⇒ x = 8 Therefore, the numbers are 2x=16 and 3x=24
∴ The required sum = (16 + 24) = 40
The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. The sum of the numbers is ___.