Question

The largest number of unpaired electrons: $F,N,S^{2-},M{g}^{2+},S{c}^{3+},T{i}^{3+}$

• A. $N$
• B. $M{g}^{2+}$
• C. $F$
• D. $T{i}^{3+}$

Answer 1

Answer: (A)

$N$

$F=\left[He\right]2s^{2}2p^5$

$N=\left[He\right]2s^{2}2p^3$

$S^{2-}=\left[He\right]2s^{2}3p^5$

$M{g}^{2+}=\left[Ne\right]$

$S{c}^{3+}=\left[Ar\right]$

$T{i}^{3+}=\left[Ar\right]3d^1$

Nitrogen has maximum 3 unpaired electrons.

Hence, the correct option is $A$