The largest possible bond angle is observed in:

B F_{3}

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B e F_{2}

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N F_{3}

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C F_{4}

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Solution

The correct option is D $N F_{3}$
In $B F_{3};$ , but we see in $N F_{3};$ have largest distance due to the lone pair electronegative element fluorine and distance between worries into the electronegative element fluorine.

So $N F_{3}$ have largest possible bond angle.

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