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Question
The latent heat of fusion of solid water at 0∘ is 80 cal/g. How much heat is required to convert 4 g of ice at 0∘C to water at 0∘C ?
The latent heat of fusion of solid water at 0∘ is 80 cal/g. How much heat is required to convert 4 g of ice at 0∘C to water at 0∘C ?
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Solution
The correct option is D 320 cal
Given,
Latent heat of fusion of solid water at 0∘C : 80 cal/g
Mass of ice : 4 g
Heat required = Latent heat × mass
= 80 cal/g×4 g=320 cal
The heat required to convert 4 g of ice at 0∘C to water at 0∘C is 320 cal.
320 cal
Given,
Latent heat of fusion of solid water at 0∘C : 80 cal/g
Mass of ice : 4 g
Heat required = Latent heat × mass
= 80 cal/g×4 g=320 cal
The heat required to convert 4 g of ice at 0∘C to water at 0∘C is 320 cal.
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