The latus rectum of the conic section x2-a2 - y2-b2 - 1 whose eccentricity - e is-

The correct option is C 2a ( 1 e^2 ) We know latus rectum of ellipse x^2/a^2 + y^2/b^2 = 1 is 2l=2b^2a Also for ellipse b^2=a^2(1 e^2) ...

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General Equation of Hyperbola

The latus rec...

Question

The latus rectum of the conic section $\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1$ whose eccentricity = $e$ is:

\frac{2 a^{2}}{b}

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\frac{2 b}{a^{2}}

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2 a (1 - e^{2})

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2 b (1 - e^{2})

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Solution

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