The LCM of two numbers is $(a + b)$ and their HCF is $K (a - b)$ . If one number is K, then the other number is

\frac{K a}{b}

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Kab

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a^{2} - b^{2}

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\frac{K a + b}{K a - b}

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Solution

The correct option is C $a^{2} - b^{2}$
Given,
LCM = $(a+b)$
HCF= K\times (a-b)$
One number= $k$
Let the other number be $x$
$∴ x = \frac{L C M \times H C F}{O n e n u m b e r}$
$= \frac{(a + b) k (a - b)}{k}$
$= (a^{2} - b^{2})$
The other number is $(a^{2} - b^{2})$

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