Question

The leakage of a tap, attached to a water dispenser of 5L capacity, is 700 mL in a day. Calculate the water that would remain in the dispenser after 2 days.

Answer 1

Daily water Leakage = 700 mL​

Water leakage of 2 days =
700 mL + 700 mL​
= 1400 mL​

Total capacity of water dispenser = 5 L​

We know that 1 L = 1000 mL​

So, water dispenser = 5L x 1000 ​
= 5000 mL​

Remaining water = 5000 mL – 1400 mL ​
= 3600 mL​
= 3 L 600 mL