The length, breadth and height of a cuboidal reservoir is $7 m, 6 m$ and $15 m$ respectively. $8400$ L of water is pumped out from the reservoir. Find the fall in the water level in the reservoir.

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Solution

Length of a cuboidal reservoir $= 7 m$
Breadth of a cuboidal reservoir $= 6 m$
Height of a cuboidal reservoir $= 15 m$
Capacity of cuboidal reservoir $= l \times b \times h = 7 \times 6 \times 15 = 630 m^{3}$
If $8400 L$ of water is pumped out,
In meter cubic $= \frac{8400}{1000} = 8.4 m^{3}$ $[∵ 1 m^{3} = 1000 L]$
Volume reduced after pumped out $= 630 - 8.4 = 621.6 m^{3}$
length $\times$ breadth $\times$ reduced height $= 621.6 m^{3}$
$7 \times 6 \times h^{'} = 621.6$
$h^{'} = \frac{621.6}{42} = 14.8 m$
Hence, the reduced height will be $14.8 m$

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The length, breadth and height of a cuboidal reservoir is 7 m,6 m and 15 m respectively. 8400 L of water is pumped out from the reservoir. Find the fall in the water level in the reservoir.

The length, breadth and height of a cuboidal reservoir is $7 m, 6 m$ and $15 m$ respectively. $8400$ L of water is pumped out from the reservoir. Find the fall in the water level in the reservoir.