The length, breadth and height of a godown are $15$ $m$ , $12$ $m$ and $9$ $m$ respectively. Cubic blocks of side $3$ $m$ are placed in the godown. Find how may blocks can be placed in the godown.

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Solution

Given, $l = 15$ $m$ , $b = 12$ $m$ , $h = 9$ $m$
Volume of godown $(V) = l \times b \times h$
$= 15 \times 12 \times 9$
$= 180 \times 9$
$= 1620 m^{3}$
Volume of a cubic block of side $3$ $m$ $= 3 \times 3 \times 3 = 27 m^{3}$
Number of blocks in a godown $= \frac{Volume of godown}{Volume of a cubic block}$
$= \frac{1620}{27}$ $= 60$

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The length, breadth and height of a godown are 15 m, 12 m and 9 m respectively. Cubic blocks of side 3 m are placed in the godown. Find how may blocks can be placed in the godown.

Given, l=15 m, b=12 m, h=9 mVolume of godown (V)=l×b×h=15×12×9=180×9=1620m3 Volume of a cubic block of side 3 m =3×3×3=27m3Number of blocks in a godown =Volume of godownVolume of a cubic block=162027 =60

The length, breadth and height of a godown are $15$ $m$ , $12$ $m$ and $9$ $m$ respectively. Cubic blocks of side $3$ $m$ are placed in the godown. Find how may blocks can be placed in the godown.