The length, breadth and height of a room are $5 m$ , $4 m$ and $3 m$ respectively. Find the cost white washing the walls of the room and ceiling at the rate of $R s . 7.50$ per $m^{2}$ .

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Solution

Given:
$L = 5 m$ , $B = 4 m$ , $H = 3 m$
Area to be white-washed (Four walls) $=$ Area of cuboid $-$ Area of base.

$= 2 l h + 2 b h + 2 l b - l b$

$= 2 l h + 2 b h + l b$

$= [2 \times 5 \times 3 + 2 \times 4 \times 3 + 5 \times 4] m^{2}$

$= 74 m^{2}$

Cost of white washing per $m^{2}$ area $=$ Rs. $7.50$

Cost of white washing $74 m^{2}$ area $= 74 \times 7.50$ $= R s .555$

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The length, breadth and height of a room are 5 m, 4 m and 3 m respectively. Find the cost white washing the walls of the room and ceiling at the rate of Rs. 7.50 per m2.

Given:L=5 m, B=4 m, H=3 mArea to be white-washed (Four walls) = Area of cuboid − Area of base.=2lh+2bh+2lb−lb=2lh+2bh+lb=[2×5×3+2×4×3+5×4] m2=74 m2Cost of white washing per m2 area = Rs.7.50Cost of white washing 74 m2 area =74×7.50 =Rs.555

The length, breadth and height of a room are $5 m$ , $4 m$ and $3 m$ respectively. Find the cost white washing the walls of the room and ceiling at the rate of $R s . 7.50$ per $m^{2}$ .