The length, breadth and height of a room are $6$ m, $5.4$ m and $4$ m respectively, then the area of its four-walls is $91.2 m^{2}$

If true then enter $1$ else 0

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Solution

Area of four walls = 2(lh+bh)
= 2(6 $\times$ 4+5.4 $\times$ 4)
= 91.2 $m^{2}$

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The length, breadth and height of a room are 6 m, 5.4 m and 4 m respectively, then the area of its four-walls is 91.2m2If true then enter 1 else 0

Area of four walls = 2(lh+bh) = 2(6×4+5.4×4) = 91.2 m2

The length, breadth and height of a room are $6$ m, $5.4$ m and $4$ m respectively, then the area of its four-walls is $91.2 m^{2}$

If true then enter $1$ else 0

Area of four walls = 2(lh+bh)
= 2(6 $\times$ 4+5.4 $\times$ 4)
= 91.2 $m^{2}$