The length of a pendulum is measured as 20.0 cm. The time interval for 100 oscillations is measured as 90 s with a stop watch of 1 s resolution. Find the approximate percentage error in g to the nearest integer.

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Q. The least count of a stop-watch is

(1 / 5) s

. The time of

20

oscillations of a pendulum is measured to be

25 s

. What is the maximum percentage error in this measurement ?

Q. The period of oscillation of a simple pendulum of length l is given by

T = 2 π \sqrt{l / g}

. The length l is about 10 cm and is known to 1 mm accuracy. The period of oscillation is about 0.5 s. The time of 100 oscillations has been measured with a stop watch of 1 s resolution. Find the percentage error in the determination of g.

Q. The least count of a stop watch is

\frac{1}{5} s

. The time of 20 oscillations of a pendulum is measured to be

25 s

. What is the maximum percentage error in this measurement ?

The period of oscillation of a simple pendulum is $T = 2 π \sqrt{\frac{L}{g}}$ . Measure of $L$ is $20.0 c m$ known to $1 m m$ accuracy and time for $100$ oscillations of the pendulum is found to be $90 s$ using a wrist watch of $1 s$ resolution. The accuracy in the determination of $g$ ?