The length of a pendulum is measured as 20.0 cm.The time interval for 100 oscillations is measured as 90s with a stop watch of 1s resolution.The accuracy in the determination of 'g' is-1)1% 2)7% 3)3% 4)4

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The period of oscillation of a simple pendulum is $T = 2 π \sqrt{\frac{L}{g}}$ . Measure of $L$ is $20.0 c m$ known to $1 m m$ accuracy and time for $100$ oscillations of the pendulum is found to be $90 s$ using a wrist watch of $1 s$ resolution. The accuracy in the determination of $g$ ?

Q. The period of oscillation of a simple pendulum is

T = 2 π \sqrt{\frac{L}{g}}

. The measured value of

L

20.0 c m

known to

1 m m

accuracy and time for

100

oscillations of the pendulum is found to be

90 s

using a wristwatch of

1 s

resolution. What is the accuracy in the determination of

g

The period of oscillation of a simple pendulum is $T = 2 π \sqrt{\frac{L}{g}}$ . Measured value of L is 20.0 cm known to 1 mm accuracy and time for 100 oscillation of the pendulum is found to be 90 s using wrist watch of 1 s resolution. The accuracy in the determination of g is:

Q. The period of oscillation of a simple pendulum is T =

2 π \sqrt{\frac{L}{g}}

. Measured value of L is 10 cm known to 1 mm accuracy and time for 100 oscillations of the pendulum is found to be 50 s using a wrist watch of 1 s resolution. What is the accuracy in the determination of g?

Q. The period of oscillation of a simple pendulum of length l is given by

T = 2 π \sqrt{l / g}

. The length l is about 10 cm and is known to 1 mm accuracy. The period of oscillation is about 0.5 s. The time of 100 oscillations has been measured with a stop watch of 1 s resolution. Find the percentage error in the determination of g.

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