The length of a plot is five times its breadth. A playground measuring $245 m^{2}$ occupies half of the total area of the plot. What is the length of the plot?

35 \sqrt{2} m

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175 \sqrt{2} m

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490 m

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5 \sqrt{2} m

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Solution

The correct option is A $35 \sqrt{2} m$
Let breadth of plot $= x m$
$∴$ Length $= 5 x m$
As per the question
$\frac{5 x^{2}}{2} = 245$
$x^{2} = \frac{245 \times 2}{5}$
$x^{2} = 98$
$x = \sqrt{98}$
$x = 7 \sqrt{2} m$
$∴$ Length $= 5 \times 7 \sqrt{2} = 35 \sqrt{2} m$

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Q. The length of a rectangular playground is

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longer than its breadth. If the area of the playground is

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, find the length and breadth of the field.

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The length of a plot is five times its breadth. A playground measuring 245m2 occupies half of the total area of the plot. What is the length of the plot?

The correct option is A 35√2mLet breadth of plot =x m∴ Length =5x mAs per the question5x22=245x2=245×25x2=98x=√98x=7√2 m∴ Length =5×7√2=35√2 m

The length of a plot is five times its breadth. A playground measuring $245 m^{2}$ occupies half of the total area of the plot. What is the length of the plot?

The correct option is A $35 \sqrt{2} m$
Let breadth of plot $= x m$
$∴$ Length $= 5 x m$
As per the question
$\frac{5 x^{2}}{2} = 245$
$x^{2} = \frac{245 \times 2}{5}$
$x^{2} = 98$
$x = \sqrt{98}$
$x = 7 \sqrt{2} m$
$∴$ Length $= 5 \times 7 \sqrt{2} = 35 \sqrt{2} m$