Solving a Quadratic Equation by Factorization Method
The length of...
Question
The length of a rectangle exceeds its breadth by 8cm and the area of the rectangle is 240cm2. The dimension of the rectangle are
A
28cm×20cm
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B
20cm×12cm
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C
16cm×24cm
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D
None of these
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Solution
The correct option is C20cm×12cm Let breadth be xcm ⇒ length =(x+8)cm ⇒(x+8)x=240 ⇒x2+8x−240=0 ⇒(x+20)(x−12)=0 ⇒x=−20,x=12 x=−20 is impossible Then, breadth =12cm and length =20cm ∴ dimensions =20cm×12cm