The length of a rectangle is 10cm and breadth 6cm. If the length is decreased by 3cm and breadth by 2cm. The decrease in the area is
32 cm2
Let ABCD be the rectangle with AB = 10cm and CB = 6cm.
Let length and breadth be decreased by 3 cm and 2 cm respectively as shown.
Area of original rectangle ABCD =10×6 cm2
Area of new rectangle AEFC=(6−2)×(10−3) = 4×7 cm2
Area of AEFC = area ABCD - area EBIF - area HFGD - area FICG
=10×6−4×3−2×7−3×2
=10×6−12−14−6
=10×6−(32)
Decrease in area = 32 cm2