The length of a rectangle is $2$ cm more than its breadth The perimeter is $48$ cm The area of the rectangle $(i n c m^{2})$ is

96

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128

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143

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144

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Solution

The correct option is B $143$
If x be the breadth of the rectangle, the length is x + 2
$∴ 2 [(x + 2) + x] = 48 \Rightarrow x = 11$
Area $= 13 \times 11 = 143 c m^{2}$

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The length of a rectangle is 2 cm more than its breadth The perimeter is 48 cm The area of the rectangle (incm2) is

The correct option is B 143If x be the breadth of the rectangle, the length is x + 2∴2[(x+2)+x]=48⇒x=11Area =13×11=143cm2

The length of a rectangle is $2$ cm more than its breadth The perimeter is $48$ cm The area of the rectangle $(i n c m^{2})$ is

The correct option is B $143$
If x be the breadth of the rectangle, the length is x + 2
$∴ 2 [(x + 2) + x] = 48 \Rightarrow x = 11$
Area $= 13 \times 11 = 143 c m^{2}$