Question

The length of a rectangle is three times its breadth. If the area of the rectangle is $1875sq.cm$, find its perimeter.

Answer 1

Given,
The length of a rectangle is three times its breadth.
The area of the rectangle $=1875sq.cm$
Let breadth of rectangle $=b$
Thus, length of the rectangle $=3\times \left(b\right)$
The area of the rectangle is given by:
$A=$ Length $\times$Breadth
$\Rightarrow 1875=3b\times b$
$\Rightarrow b^2=\frac{1875}{3}=625$
$\therefore b=\sqrt{625}=25cm$
Thus, length of the rectangle
$=3b=3\times 25=75cm$

We have,
Length of the rectangle $=75cm$
Breadth of rectangle $=25cm$
The perimeter of the rectangle is given by:
$P=2\left(\text{Length+Breadth}\right)$
$=2(75+25)$
$=2\left(100\right)$
$=200$
Therefore, the perimeter of the rectangle is $200cm.$