Question

The length of a rectangular park is thrice its breadth. If the perimeter of the park is $168m$, then find its dimensions.

Answer 1

Let length$=$x

Then, $x=3$Breadth

$\Rightarrow B=\frac{x}{3}$

Area$=x\cdot \frac{x}{3}$

Perimeter$=2(x+\frac{x}{3})=168$m.

$2\times \frac{4x}{3}=168$

$\Rightarrow x=\frac{3\times 168}{8}$

$x=63$m.

Length$=126$m

Breadth$=\frac{63}{3}=21$m.