The length of a room doubles its breadth. Its height is $3 m$ . The area of $4$ walls excluding a door of dimensions $4 m 2 m$ is $100 m^{2}$ . Find its volume.

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Solution

According to question
$l = 2 b; h = 3$
$2 (l + b) h = 100 + 8$
$2 (3 b) 3 = 108$
$18 b = 108$
$b = 6, l = 12$
$∴$ Volume $= 6 \times 12 \times 3$
$= 216 ㎥$

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The length of a room doubles its breadth. Its height is 3 m. The area of 4 walls excluding a door of dimensions 4m 2m is 100 m2. Find its volume.

According to questionl=2b;h=32(l+b)h=100+82(3b)3=10818b=108b=6,l=12∴Volume =6×12×3=216㎥

The length of a room doubles its breadth. Its height is $3 m$ . The area of $4$ walls excluding a door of dimensions $4 m 2 m$ is $100 m^{2}$ . Find its volume.

According to question
$l = 2 b; h = 3$
$2 (l + b) h = 100 + 8$
$2 (3 b) 3 = 108$
$18 b = 108$
$b = 6, l = 12$
$∴$ Volume $= 6 \times 12 \times 3$
$= 216 ㎥$