The length of a simple pendulum executing simple harmonic motion is increased by 10%. The percentage increase in the time period of the pendulum due to increased length will be:
The correct option is A 5%
Step 1, Given data
The length of the pendulum is increased by 10%
Step 2, Finding percentage change in the time period
Let the length of the simple pendulum be ′l′.
Let the time period of oscillation of a simple pendulum be ′T′.
Then we can write
T=2π√lg
From the above equation
∵T∝l12
Or we can write
⇒ΔTT=12(Δll) ...(i)
Now,
Since fractional change in length of pendulum is,
Δll=10100=0.1
substituting in Eq.(i)
⇒ΔTT=0.05
Hence % change in time period of pendulum is.
ΔTT×100=5%
The percentage increase in the time period of the pendulum will be 5%