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Question

The length of a simple pendulum executing simple harmonic motion is increased by 10%. The percentage increase in the time period of the pendulum due to increased length will be:

A
10%
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B
5%
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C
15%
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D
20%
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Solution

The correct option is A 5%
Step 1, Given data

The length of the pendulum is increased by 10%

Step 2, Finding percentage change in the time period
Let the length of the simple pendulum be l.
Let the time period of oscillation of a simple pendulum be T.

Then we can write
T=2πlg

From the above equation

Tl12

Or we can write
ΔTT=12(Δll) ...(i)

Now,
Since fractional change in length of pendulum is,
Δll=10100=0.1
substituting in Eq.(i)
ΔTT=0.05
Hence % change in time period of pendulum is.
ΔTT×100=5%
The percentage increase in the time period of the pendulum will be 5%


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