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Double Helical Structure of DNA

The length of...

Question

The length of DNA molecule greatly exceeds the dimensions of the nucleus in eukaryotic cells. How is then the DNA accommodated inside the nucleus?

A

Deletion of non-essential genes

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B

Super-coiling in nucleosomes

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C

DNAase digestion

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D

Through elimination of repetitive DNA

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Solution

The correct option is A Super-coiling in nucleosomes
DNA is too lengthy hence kept as condensed, super-coiled, and wrapped around histones proteins as nucleosomes in chromosomes.
Supercoiling of DNA reduces the space and allows for much more DNA to be packaged inside nucleus.

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Q. The length of the DNA molecule greatly exceeds the dimensions of the nucleus in eukaryotic cells. How is this DNA accommodated?

Q. The length of DNA molecule greatly exceeds the dimensions of the nucleus in eukaryotic cells. How is this DNA accomodated?

Q. In the eukaryotes the DNA molecules are organised withing the nucleus. How is the DNA molecules organised in a bacterial cell in the absence of nucleus?

Q. Assertion: Eukaryotic genome is classified into highly repetitive, moderately repetitive, and single-copy DNA on the basis of reiteration.
Reason: Reassociation kinetics of repetitive DNA is slower than the non-repetitive DNA.

Q. Following steps are involved in cloning a eukaryotic gene in a bacterial plasmid vector.
I. Introduction of cloning vector into cells.
II. Insertion of eukaryotic DNA into the vector.
III. Identification of cell clones that carry the inserted eukaryotic gene.
IV. Isolation of the vector and the eukaryotic gene-source DNA.
V. Cloning of cells (and foreign DNA).
Which of the following statemet is the correct reason for the insertion of eukaryotic DNA into the plasmid vector, the sticky ends formed by digestion of both DNA types with the same restriction enzyme may join in a recombinant molecule?

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