The length of rectangle is twice it's width. If it's perimeter is 54 cm , find it's length

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Solution

Let l be length and b be width.
Length is 2ce width means
l=2b

Perimeter =2(l+b)
=2(2b+b)
=23b
=6b
Given perimeter is 54
So 6b=54
b=54/6
=9
So l=29=18
So length is 18 cm

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The length of rectangle is twice it's width. If it's perimeter is 54 cm , find it's length

Let l be length and b be width. Length is 2ce width means l=2b Perimeter =2(l+b) =2(2b+b) =2*3b =6b Given perimeter is 54 So 6b=54 b=54/6 =9 So l=2*9=18 So length is 18 cm

Let l be length and b be width.
Length is 2ce width means
l=2b

Perimeter =2(l+b)
=2(2b+b)
=23b
=6b
Given perimeter is 54
So 6b=54
b=54/6
=9
So l=29=18
So length is 18 cm