The length of tangent drawn from the point $(1, 1)$ to the circle $x^{2} + y^{2} + 8 x + 20 y + 70 = 0$ is units.

Open in App

Solution

Length of tangent drawn from any point to a given circle is represented by
$L = \sqrt{S_{1}}$
$= \sqrt{1 + 1 + 8 + 20 + 70} = 10$ units

Suggest Corrections

Similar questions

(- 1, 2)

x^{2} + y^{2} - 8 x + 5 y - 7 = 0

x^{2} + y^{2} + 15 x - 17 y + c^{2} = 0

x^{2} + y^{2} + 15 x - 17 y + 21 = 0 i s \sqrt{5}

c

x^{2} + y^{2} = 1, x^{2} + y^{2} + 8 x + 15 = 0, x^{2} + y^{2} + 10 y + 24 = 0

x^{2} + y^{2} - 4 x + 6 y - 4 = 0

x^{2} + y^{2} - 4 x + 6 y = 0

x^{2} + y^{2} + 2 g x + 2 f y + c_{1} = 0

x^{2} + y^{2} + 2 g x + 2 f y + c = 0

Join BYJU'S Learning Program