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Question

# The length of tangent from the point (âˆ’1,2) to the circle x2+y2âˆ’8x+5yâˆ’7=0.

A
1
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B
4
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C
2
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D
6
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Solution

## The correct option is B 4The given equation of the circle can be written as (x−4)2+(y+52)2−16−254−7=0or, (x−4)2+(y+52)2=1174So, centere of the circle is (4,−52) and radius is √1172 units.Now distance between the point (−1,2) and (4,−52) is 1812 units which is greater than the radius of the circle.So, the point (−1,2) lies outside of the circle.The length of the tangent from the point (−1,2) to the circle x2+y2−8x+5y−7=0 is √(−1)2+22+8+10−7=√16=4 units.

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