The length of the fence of a rectangled shaped field ABCD is 130 m and side AB is 60m , find the area of the field.

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Solution

The Length of $A B = 60 m$
The Perimeter is given as $2 (l + b) = 130 60 + b = 65 b = 5 m$
The area of field is $60 \times 5 = 300 m^{2}$

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Length of the fence of a trapezium-shaped field ABCD is 120 m. If BC = 48 m, CD = 17 m and AD = 40 m, find the area of this field, given that side AB is perpendicular to the parallel sides AD and BC.

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The length of the fence of a rectangled shaped field ABCD is 130 m and side AB is 60m , find the area of the field.

The Length of AB=60mThe Perimeter is given as 2(l+b)=13060+b=65b=5mThe area of field is 60×5=300m2

The Length of $A B = 60 m$
The Perimeter is given as $2 (l + b) = 130 60 + b = 65 b = 5 m$
The area of field is $60 \times 5 = 300 m^{2}$