Question

The length of the minute hand of a clock is $14cm.$ The area swept by the minute hand between $3:20$ and $3:45$ is

• A. $256.66c{m}^2$
• B. $2.566c{m}^2$
• C. $2560c{m}^2$
• D. $0.2566c{m}^2$

Answer 1

The correct option is A

$256.66c{m}^2$

When the minute hand moves from $3:20$ to $3:45,$ the angle it covers is ${150}^{\circ }$

$\therefore$ Required area $=(\frac{150}{360}\times \frac{22}{7}\times 14\times 14)=256.66c{m}^2$