Question

The length of the minute hand of a clock is $14cm$. If minute hand moves from $1$ to $10$ on the dial, then an area of ................... ${cm}^2$ will be covered.

• A. $462$
• B. $154$
• C. $308$
• D. $616$

Answer 1

The correct option is A $462$

For $r=14cm$ and $\theta =\frac{360\times 9}{12}={270}^o$
Area of the minor sector $=\frac{\pi r^2\theta }{360}=\frac{22}{7}\times 14\times 14\times \frac{270}{360}=462{cm}^2$