Question

The length of the minute hand of a clock is 14cm. The area swept by the minute hand between 3: 20 and 3: 45 is __ .

• A. $256c{m}^2$
• B. $2.56c{m}^2$
• C. $2560c{m}^2$
• D. $0.256c{m}^2$

Answer 1

The correct option is A

$256c{m}^2$

When the minute hand moves from 3:20 to 3:45, the angle it covers is ${150}^{\circ }$

$\therefore$ Required area $=(\frac{150}{360}\times \frac{22}{7}\times 14\times 14)c{m}^2=256c{m}^2$