The length of the shadow of a vertical pole $9 m$ high, when the suns altitude is $30^{o}$ , is (in $c m$ ):

3 \sqrt{3}

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9

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9 \sqrt{3}

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18 \sqrt{3}

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Solution

The correct option is C $9 \sqrt{3}$
Let the length of the shadow be $B C = l$
Given angle of elevation of pole is $30^{\circ}$
$A B$ is the pole of height $9 m$
In $△ A B C, tan 30^{\circ} = \frac{9}{l}$
$⟹ l = 9 cot 30^{\circ} = 9 \sqrt{3}$
Length of the shaow is $9 \sqrt{3}$

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Similar questions

Q. Find the angle of elevation of the sun (suns altitude) when the length of the shadow of a vertical pole is equal to its height.

Q. A

5

60

cm high vertical pole casts a shadow

3

20

cm long. Find at the same time the length of the shadow cast by another pole

10

50

cm high.

A $5 m 60 c m$ high vertical pole casts a shadow $3 m 20 c m$ long. Find at the same time the length of the shadow cast by another pole $10 m 50 c m$ high.

Question 09.1 .
A 5 m 60 cm high vertical pole casts a shadow 3 m 20 cm long. Find at the same time the length of the shadow cast by another pole 10 m 50 cm high.

A 5 m 60 cm high vertical pole casts a shadow 3 m 20 cm long. Find at the same time −

(i) the length of the shadow cast by another pole 10 m 50 cm high

(ii) the height of a pole which casts a shadow 5 m long.

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The length of the shadow of a vertical pole 9 m high, when the suns altitude is 30o, is (in cm):

The correct option is C 9√3Let the length of the shadow be BC=lGiven angle of elevation of pole is 30∘AB is the pole of height 9 mIn △ABC,tan30∘=9l⟹l=9cot30∘=9√3Length of the shaow is 9√3

The length of the shadow of a vertical pole $9 m$ high, when the suns altitude is $30^{o}$ , is (in $c m$ ):

The correct option is C $9 \sqrt{3}$
Let the length of the shadow be $B C = l$
Given angle of elevation of pole is $30^{\circ}$
$A B$ is the pole of height $9 m$
In $△ A B C, tan 30^{\circ} = \frac{9}{l}$
$⟹ l = 9 cot 30^{\circ} = 9 \sqrt{3}$
Length of the shaow is $9 \sqrt{3}$