The length of the side of a small squares is $80 m$ . The length of the side of a big square is $20 m$ more then the small square. Find the perimeter of the big square.

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Solution

Given, the length of the side of a small square is $80 m$ and the length of the side of a big square is $20 m$ more then the small square.
Then the side of the big square is $80 + 20 = 100$ m.
Then the perimeter of the big square is $4 \times 100 = 400$ m.

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The length of the side of a small squares is 80 m. The length of the side of a big square is 20m more then the small square. Find the perimeter of the big square.

Given, the length of the side of a small square is 80 m and the length of the side of a big square is 20m more then the small square.Then the side of the big square is 80+20=100 m.Then the perimeter of the big square is 4×100=400 m.

The length of the side of a small squares is $80 m$ . The length of the side of a big square is $20 m$ more then the small square. Find the perimeter of the big square.

Given, the length of the side of a small square is $80 m$ and the length of the side of a big square is $20 m$ more then the small square.
Then the side of the big square is $80 + 20 = 100$ m.
Then the perimeter of the big square is $4 \times 100 = 400$ m.