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Byju's Answer
Standard XII
Physics
String Open at One End
The length of...
Question
The length of the string is
216
×
10
−
x
m
.
Find the value of x.
A
1
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B
2.16
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C
8
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D
5
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Solution
The correct option is
B
2.16
For
n
t
h
harmonic for string taut at two ends,
l
=
n
λ
2
Thus
λ
∝
1
n
Thus
n
+
1
n
=
0.54
0.48
⟹
n
=
8
⟹
l
=
8
×
0.54
2
=
2.16
m
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