The lengths of the parallel sides of a trapezium are 19 cm and 13 cm and its area is 128 $c m^{2}$ . The distance between the parallel sides is
(a) 9 cm (b) 7 cm
(c) 8 cm (d) 12.5 cm

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Solution

Length of parallel sides are 19 cm and 13 cm
Area of trapezium = 128 $c m^{2}$
$∴$ Distance between then
= $\frac{A r e a \times 2}{Sum of parallel sides} = \frac{128 \times 2}{19 + 13} = \frac{128 \times 2}{32} = 8 c m$

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The lengths of the parallel sides of a trapezium are 19 cm and 13 cm and its area is 128 cm2. The distance between the parallel sides is (a) 9 cm (b) 7 cm (c) 8 cm (d) 12.5 cm

Length of parallel sides are 19 cm and 13 cm Area of trapezium = 128 cm2 ∴ Distance between then = Area×2Sum of parallel sides=128×219+13=128×232=8cm

The lengths of the parallel sides of a trapezium are 19 cm and 13 cm and its area is 128 $c m^{2}$ . The distance between the parallel sides is
(a) 9 cm (b) 7 cm
(c) 8 cm (d) 12.5 cm

Length of parallel sides are 19 cm and 13 cm
Area of trapezium = 128 $c m^{2}$
$∴$ Distance between then
= $\frac{A r e a \times 2}{Sum of parallel sides} = \frac{128 \times 2}{19 + 13} = \frac{128 \times 2}{32} = 8 c m$