The ligand $N (C H_{2} C H_{2} N H_{2})_{3}$ is

Tridentate

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Pentadentate

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Tetradentate

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Bidentate

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Solution

The correct option is C Tetradentate
You already know that nitrogen when bonded to 3 species has a lone pair of electrons. Looking closely at this compound, there are 4 nitrogen atoms right? One central nitrogen atom which is connected to 3 amino ethane groups. Each of the amino ethane groups have a nitrogen which is bonded to 2 hydrogens and one carbon.
So clearly, all the nitrogen atoms only have 3 bonds here, making the lone pairs on each of them available for bonding with a metal.
Hence, the number of donor atoms are 4. Hence it is tetradentate.

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N (C H_{2} C H_{2} N H_{2})_{3}

N (C H_{2} C H_{2} N H_{2})_{3}

n C H_{2} = C H_{2} \to [- C H_{2} - C H_{2} -]_{n}

n C H_{2} = C H_{2} \to (- C H_{2} - C H_{2} -)_{n}

100

100

n C H_{2} = C H_{2} \to (C H_{2} - C H_{2})_{n}

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