The ligand $N (C H_{2} C H_{2} N H_{2})_{3}$ :

bidentate

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tridentate

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tetradentate

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pentadentate.

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Solution

The correct option is A tetradentate
$H_{2} ∙ ∙ N - C H_{2} - C H_{2} - ∙ ∙ N | C H_{2} | C H_{2} |_{∙}^{∙} N H_{2} - C H_{2} - C H_{2} - ∙ ∙ N H_{2}$
Number of donor atoms in $N (C H_{2} C H_{2} N H_{2})_{3}$ is four hence it is a tetradentate ligand. Each nitrogen atom is a donor atom.

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d - o r b i t a l s

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