Question

# The light of wavelength $$5000\overset {\circ}{A}$$ falls on a photosensitive plate of work function $$1.9\ eV$$. The kinetic energy of the emitted photoelectrons is :

A
0.58 eV
B
2.48 eV
C
1.24 eV
D
1.18 eV

Solution

## The correct option is A $$0.58\ eV$$The energy of photon $$E = \dfrac {hc}{\lambda}$$$$= \dfrac {12375}{\lambda}eV$$$$E = \dfrac {12375}{5000}$$$$= 2.48\ eV$$The kinetic energy of equation of photoelectric$$E_{k} = E - W$$$$= 0.58\ eV$$.Physics

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