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Question

The light of wavelength $$5000\overset {\circ}{A}$$ falls on a photosensitive plate of work function $$1.9\ eV$$. The kinetic energy of the emitted photoelectrons is :


A
0.58 eV
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B
2.48 eV
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C
1.24 eV
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D
1.18 eV
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Solution

The correct option is A $$0.58\ eV$$
The energy of photon $$E = \dfrac {hc}{\lambda}$$
$$= \dfrac {12375}{\lambda}eV$$
$$E = \dfrac {12375}{5000}$$
$$= 2.48\ eV$$
The kinetic energy of equation of photoelectric
$$E_{k} = E - W$$
$$= 0.58\ eV$$.

Physics

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