The limiting line in Balmer series will have a frequency of :
A
32.29 × 1015 s−1
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B
3.65 × 1014 s−1
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C
-8.22 × 1014 s−1
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D
8.22 × 1014 s−1
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Solution
The correct option is D 8.22 × 1014 s−1 The limiting line of Balmer series refers to the transaction from ∞ to 2nd orbital. v = 3.29 × 1015 (1n21- 1n22) s− =3.29 × 1015×14 = 8.22 × 1014 s−1