The limiting line of Paschen series of H atom will have a frequency equal to: R=1.097×107m−1
A
3.65×1014 Hz
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B
3.65×1016 Hz
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C
4.95×1017 Hz
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D
3.63×1012 Hz
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Solution
The correct option is A3.65×1014 Hz The limiting line will be the shortest line in the Paschen series. It is observed when an electron drops from an orbit with n=∞ to an orbit with n=3.
Wave length of this line is given by: 1λ=R(1n12−1n22)
Given: R=1.097×107m−1
Substituting the values of n and R we get: 1λ=1.097×107×(132−1∞2)λ=8.20×10−7m−1
So c = νλ
where ν = frequency of the transition ν = 3×1088.20×10−7 = 3.65×1014 Hz