The limiting molar conductivity for NaCl,KBr and KCl are 126,152 & 150 S.cm^2mol^-1 respectively.then molar conductivity for NaBr is

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Q. The limiting molar conducticities

\land^{0}

for NaCl,KBr and KCl are 126,152 and

150 S c m^{2} m o l^{- 1}

respectively. The

\land_{m}^{0}

for NaBr is:

The limiting molar conductivities $\land^{0}$ for $N a C l, K B r$ and $K C l$ are $126, 152$ and $150$ $S$ $c m^{2} m o l^{- 1}$ respectively. The $\land^{0}$ for $N a B r$ is :

Q. The limiting molar conductivities of

N a C l

K B r

and

K C l

are 126, 152 and 150

S c m^{2} m o l^{- 1}

respectively. The limiting molar conductivity for

N a B r

is:

The limiting molar conductivity for KCl, NaBr and NaCl are 100, 120, 130 S cm^-2mol^-1 respectively. Calculate the limiting molar conductivity for KBr?

Q. The limiting molar conductivities

λ^{\circ}

for

N a C l, K B r

and

K C l

are

126, 152

and

150 S c m^{2} m o l^{- 1}

respectively. The

λ^{\circ}

for

N a B r

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