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Question

The line 2x+3y=6, 2x+3y=8 cut the X-axis at a A,B respectively. A line L=o drawn through the point (2,2) meets the X-axis at C in such a way that abscissae of A,B,C are in arithmetic progression. Then the equation of the line L is


A

2x+3y=10

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B

3x+2y=10

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C

2x-3y=10

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D

3x-2y=10

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Solution

The correct option is A

2x+3y=10


Clearly A=(3,0); B=(4,0)

'C' must be either (2,0) or (5,0) as abscissae are in AP

If c=(2,0) then required line is x=2

If c=(5,0) then required line is 2x+3y-10=0


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