The line 2x+3y=6, 2x+3y=8 cut the X-axis at a A,B respectively. A line L=o drawn through the point (2,2) meets the X-axis at C in such a way that abscissae of A,B,C are in arithmetic progression. Then the equation of the line L is
2x+3y=10
Clearly A=(3,0); B=(4,0)
'C' must be either (2,0) or (5,0) as abscissae are in AP
If c=(2,0) then required line is x=2
If c=(5,0) then required line is 2x+3y-10=0