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Parametric Form of Tangent: Ellipse

The line draw...

Question

The line drawn from (4, -1, 2) to the point (-3, 2, 3) meets a plane at right angles at the point (-10, 5, 4), then the equation of plane is
[DSSE 1985]

A

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B

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C

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D

None of these

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Solution

The correct option is A

Required plane is, 7(x+10) - 3(y-5) - (z - 4) = 0
or 7x - 3y - z +89 = 0.

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Similar questions

R^{3},

P_{1} : x - y + z = 3

L : \frac{x - 1}{3} = \frac{y - 2}{2} = \frac{z + 1}{1}

be the equation of plane and straight line respectively. Let

Q

be the image of the point

(- 1, 2, 3)

with respect to the plane

P_{1} .

Then the equation of the plane

P_{2}

passing through

Q

and containing the line

L

Q. If the line drawn from (4, −1, 2) meets a plane at right angles at the point (−10, 5, 4), find the equation of the plane.

Q. The equation of the plane through the intersection of the planes x + 2y + 3z = 4 and 2x + y − z = −5 and perpendicular to the plane 5x + 3y + 6z + 8 = 0 is

(a) 7x − 2y + 3z + 81 = 0
(b) 23x + 14y − 9z + 48 = 0
(c) 51x − 15y − 50z + 173 = 0
(d) None of these

4 x - 3 y + 2 = 0

is rotated through an angle of

\frac{π}{4}

in clockwise direction about the point

(1, 2) .

The equation of the line in its new position is

Q. The equation of the line cutting off an intercept of 3 on the Y-axis and parallel to the line joining points A(4, -5) and B(1, 2) is .

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