The line plot below shows the weight of salt packets used in a restaurant. What is the total weight of the $\frac{1}{5}$ lb salt packets used?

\frac{2}{9}

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\frac{3}{7}

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\frac{7}{3}

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\frac{4}{5}

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Solution

The correct option is D $\frac{4}{5}$ lb
Total amount of $\frac{1}{5}$ lb of salt used $= \frac{1}{5} + \frac{1}{5} + \frac{1}{5} + \frac{1}{5} = \frac{4}{5}$ lb

The weight of all the $\frac{1}{5}$ lb packets is $\frac{4}{5}$ lb.

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Out of these packets, one packet is chosen at random.
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The line plot below shows the weight of salt packets used in a restaurant. What is the total weight of the 15 lb salt packets used?

The correct option is D 45 lbTotal amount of 15 lb of salt used =15+15+15+15=45 lb The weight of all the 15 lb packets is 45 lb.

The line plot below shows the weight of salt packets used in a restaurant. What is the total weight of the $\frac{1}{5}$ lb salt packets used?

The correct option is D $\frac{4}{5}$ lb
Total amount of $\frac{1}{5}$ lb of salt used $= \frac{1}{5} + \frac{1}{5} + \frac{1}{5} + \frac{1}{5} = \frac{4}{5}$ lb

The weight of all the $\frac{1}{5}$ lb packets is $\frac{4}{5}$ lb.