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Question

The line x2y1=0 intersects the circle x2+y2+4x2y5=0 at the points P and Q, then 5PQ is

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Solution

Given circle x2+y2+4x2y5=0
(x+2)2+(y1)2=10
Now r=10 and center C(2,1)
length of perpendicular from C on line x2y1=0 will be
d=|221|5=5
Hence PQ= length of the chord
PQ=2105=25 units

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