The liquids shown in the U-tube of uniform cross section are water and mercury. If the difference of the heights of the mercury columns is $2 c m$ , then the height $h$ of the water column is

6.8 c m

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13.6 c m

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27.2 c m

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54 c m

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Solution

The correct option is D $27.2 c m$
Equating the pressures at level of the interface we get
$h \times 1000 \times g = \frac{2}{100} \times 13600 \times g$
or $h = \frac{2 \times 13.6}{100} m = 27.2 c m$

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The liquids shown in the U-tube of uniform cross section are water and mercury. If the difference of the heights of the mercury columns is 2cm, then the height h of the water column is

The correct option is D 27.2cmEquating the pressures at level of the interface we geth×1000×g=2100×13600×gor h=2×13.6100m=27.2cm

The liquids shown in the U-tube of uniform cross section are water and mercury. If the difference of the heights of the mercury columns is $2 c m$ , then the height $h$ of the water column is

The correct option is D $27.2 c m$
Equating the pressures at level of the interface we get
$h \times 1000 \times g = \frac{2}{100} \times 13600 \times g$
or $h = \frac{2 \times 13.6}{100} m = 27.2 c m$