The given numbers are – 10, –6, –2, 2, ...
Here, a1=−10, a2=−6, a3=−2 and a4=2
Since, a2−a1=−6−(−10)
=−6+10=4
a3−a2=−2−(−6)
=−2+6=4
a4−a3=2−(−2)
=2+2=4
The difference between any two consecutive terms of the series is 4.
So, the given list forms an AP with a common difference, d = 4.