The longitudinal waves travel in a coiled spring at a rate of 4 m/s. The distance between two consecutive compressions is 20 cm. Find :

(i) Wavelength of the wave

(ii) Frequency of the wave

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Solution

Given:

Speed of wave, v = 4 m/s

Distance between two consecutive compressions is nothing but Wavelength of longitudinal wave, λ = 20 cm or 0.2 m

And for frequency of the wave motion,
f = v/ λ Hz
= 4/0.2 = 20 Hz

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The longitudinal waves travel in a coiled spring at a rate of 4 m/s. The distance between two consecutive compressions is 20 cm. Find : (i) Wavelength of the wave (ii) Frequency of the wave

Given: Speed of wave, v = 4 m/s Distance between two consecutive compressions is nothing but Wavelength of longitudinal wave, λ = 20 cm or 0.2 m And for frequency of the wave motion, f = v/ λ Hz = 4/0.2 = 20 Hz

The longitudinal waves travel in a coiled spring at a rate of 4 m/s. The distance between two consecutive compressions is 20 cm. Find :

(i) Wavelength of the wave

(ii) Frequency of the wave

Given:

Speed of wave, v = 4 m/s

Distance between two consecutive compressions is nothing but Wavelength of longitudinal wave, λ = 20 cm or 0.2 m

And for frequency of the wave motion,
f = v/ λ Hz
= 4/0.2 = 20 Hz